(2x+y)(x^2-3xy+2y^2)=

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Solution for (2x+y)(x^2-3xy+2y^2)= equation: 


Simplifying
(2x + y)(x2 + -3xy + 2y2) = 0

Reorder the terms:
(2x + y)(-3xy + x2 + 2y2) = 0

Multiply (2x + y) * (-3xy + x2 + 2y2)
(2x * (-3xy + x2 + 2y2) + y(-3xy + x2 + 2y2)) = 0
((-3xy * 2x + x2 * 2x + 2y2 * 2x) + y(-3xy + x2 + 2y2)) = 0

Reorder the terms:
((4xy2 + -6x2y + 2x3) + y(-3xy + x2 + 2y2)) = 0
((4xy2 + -6x2y + 2x3) + y(-3xy + x2 + 2y2)) = 0
(4xy2 + -6x2y + 2x3 + (-3xy * y + x2 * y + 2y2 * y)) = 0
(4xy2 + -6x2y + 2x3 + (-3xy2 + x2y + 2y3)) = 0

Reorder the terms:
(4xy2 + -3xy2 + -6x2y + x2y + 2x3 + 2y3) = 0

Combine like terms: 4xy2 + -3xy2 = 1xy2
(1xy2 + -6x2y + x2y + 2x3 + 2y3) = 0

Combine like terms: -6x2y + x2y = -5x2y
(1xy2 + -5x2y + 2x3 + 2y3) = 0

Solving
1xy2 + -5x2y + 2x3 + 2y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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